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36x^2+60x+21=0
a = 36; b = 60; c = +21;
Δ = b2-4ac
Δ = 602-4·36·21
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-24}{2*36}=\frac{-84}{72} =-1+1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+24}{2*36}=\frac{-36}{72} =-1/2 $
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